Last change
on this file since 7244 was
5827,
checked in by sudi, 16 years ago
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Adding new versions of shallow_water_domain
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File size:
3.8 KB
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Rev | Line | |
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[5535] | 1 | |
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| 2 | |
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| 3 | class AnalyticDam: |
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| 4 | |
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| 5 | def __init__(self, h0 = 5.0, h1 = 10.0, L = 2000.0): |
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| 6 | from math import sqrt |
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| 7 | |
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| 8 | self.h0 = h0 # depth upstream (m) |
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| 9 | self.h1 = h1 # depth downstream (m) |
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| 10 | self.L = L # length of domain |
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| 11 | |
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| 12 | g = 9.81 # gravity (m/s^2) |
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| 13 | |
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| 14 | c0 = sqrt(g*h0) #left celerity |
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| 15 | c1 = sqrt(g*h1) #right celerity |
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| 16 | |
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| 17 | zmin=-100.0 |
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| 18 | zmax=101.0 |
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| 19 | for i in range(100): |
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| 20 | z=(zmin+zmax)/2.0 |
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| 21 | u2=z-c0*c0/4.0/z*(1.0+sqrt(1.0+8.0*z*z/c0/c0)) |
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| 22 | c2=c0*sqrt(0.5*(sqrt(1.0+8.0*z*z/c0/c0)-1.0)) |
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| 23 | func=2.0*c1/c0-u2/c0-2.0*c2/c0 |
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| 24 | if (func > 0.0): |
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| 25 | zmin=z |
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| 26 | else: |
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| 27 | zmax=z |
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[5827] | 28 | #print 'func=',func |
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[5535] | 29 | if( abs(z) > 99.0): |
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| 30 | print 'no convergence' |
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| 31 | |
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| 32 | self.u2 = u2 |
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| 33 | self.c0 = c0 |
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| 34 | self.c1 = c1 |
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| 35 | self.c2 = c2 |
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| 36 | self.g = g |
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| 37 | self.z = z |
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| 38 | |
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| 39 | |
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| 40 | |
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| 41 | def __call__(self, C,t): |
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| 42 | |
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| 43 | from Numeric import zeros,Float |
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| 44 | from math import sqrt |
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| 45 | |
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| 46 | #t = 0.0 # time (s) |
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| 47 | h0 = self.h0 |
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| 48 | h1 = self.h1 |
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| 49 | L = self.L |
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| 50 | n = len(C) # number of cells |
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| 51 | |
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| 52 | u2 = self.u2 |
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| 53 | c0 = self.c0 |
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| 54 | c1 = self.c1 |
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| 55 | c2 = self.c2 |
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| 56 | |
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| 57 | g = self.g |
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| 58 | z = self.z |
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| 59 | |
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| 60 | u = zeros(n,Float) |
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| 61 | h = zeros(n,Float) |
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| 62 | uh = zeros(n,Float) |
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| 63 | x = C-3*L/4.0 |
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| 64 | #x = zeros(n,Float) |
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| 65 | #for i in range(n): |
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| 66 | # x[i] = C[i]-1000.0 |
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| 67 | |
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| 68 | # Upstream and downstream boundary conditions are set to the intial water |
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| 69 | # depth for all time. |
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| 70 | |
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| 71 | # Calculate Shock Speed |
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| 72 | #h2 = 7.2692044 |
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| 73 | |
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| 74 | #S2 = 2*h2/(h2-h0)*(sqrt(g*h1)-sqrt(g*h2)) |
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| 75 | #u2 = S2 - g*h0/(4*S2)*(1+sqrt(1+8*S2*S2/(g*h0))) |
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| 76 | |
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| 77 | h2=h0/(1.0-u2/z) |
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| 78 | x3=(u2-c2)*t |
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| 79 | x2=z*t |
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| 80 | x1=-c1*t |
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| 81 | x1_ = -1*L/2.0-x1 |
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| 82 | x2_ = -1*L/2.0+2*x1 |
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| 83 | #x3_ = -1*L/2.0-x3 |
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| 84 | #t=50 |
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| 85 | #x = (-L/2:L/2) |
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| 86 | for i in range(n): |
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| 87 | # Calculate Analytical Solution at time t > 0 |
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| 88 | u3 = 2.0/3.0*(sqrt(g*h1)+x[i]/t) |
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| 89 | h3 = 4.0/(9.0*g)*(sqrt(g*h1)-x[i]/(2.0*t))*(sqrt(g*h1)-x[i]/(2.0*t)) |
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| 90 | u3_ = 2.0/3.0*((x[i]+L/2.0)/t-sqrt(g*h1)) |
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| 91 | h3_ = 1.0/(9.0*g)*((x[i]+L/2.0)/t+2*sqrt(g*h1))*((x[i]+L/2.0)/t+2*sqrt(g*h1)) |
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| 92 | #if t == 30: |
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| 93 | # x[i] = 500 |
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| 94 | # print 'x2',x2 |
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| 95 | # print 'x3',x3 |
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| 96 | # print 'x1',x1 |
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| 97 | if ( x[i] <= x2_ ): |
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| 98 | #print 'here x2_=', x2_ |
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| 99 | u[i] = 0.0 |
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| 100 | h[i] = 0.0 |
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| 101 | uh [i] = u[i]*h[i] |
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| 102 | #elif ( x[i] <= x3_ ): |
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| 103 | # print 'here x3_=', x3_ |
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| 104 | # u[i] = -1*u2 |
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| 105 | # h[i] = h2 |
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| 106 | # uh[i] = u[i]*h[i] |
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| 107 | elif ( x[i] <= x1_ ): |
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| 108 | #print 'here x1_=', x1_ |
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| 109 | u[i] = u3_ |
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| 110 | h[i] = h3_ |
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| 111 | uh[i] = u[i]*h[i] |
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| 112 | #else: |
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| 113 | # u[i] = 0.0 |
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| 114 | # h[i] = h0 |
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| 115 | # uh[i] = u[i]*h[i] |
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| 116 | |
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| 117 | #elif ( x[i] <= x1/2.0 ): |
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| 118 | # u[i] = 0.0 |
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| 119 | # h[i] = h1 |
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| 120 | # uh[i] = u[i]*h[i] |
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| 121 | elif ( x[i] <= x1 ): |
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| 122 | #print 'here x1=', x1 |
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| 123 | u[i] = 0.0 |
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| 124 | h[i] = h1 |
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| 125 | uh[i] = u[i]*h[i] |
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| 126 | elif ( x[i] <= x3 ): |
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| 127 | #print 'here x3=', x3 |
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| 128 | u[i] = u3 |
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| 129 | h[i] = h3 |
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| 130 | uh[i] = u[i]*h[i] |
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| 131 | elif ( x[i] < x2 ): |
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| 132 | #print 'here x2=', x2 |
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| 133 | u[i] = u2 |
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| 134 | h[i] = h2 |
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| 135 | uh[i] = u[i]*h[i] |
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| 136 | else: |
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| 137 | #print 'here the last section' |
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| 138 | u[i] = 0.0 |
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| 139 | h[i] = h0 |
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| 140 | uh[i] = u[i]*h[i] |
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| 141 | |
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| 142 | return h , uh |
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